需求很简单，通过UIViewController.view内的任意控件获取当前UIViewController；

立马开写：

/** *    @brief    通过viewController内的view,获取Controller *  *    @param     view     subView * *    @return    UIViewController */- (UIViewController *)recursionView2ViewController:(UIView *)view{    __block UIViewController *viewController;    __block void (^blocks)(UIView *) = nil;    blocks = ^(UIView *view)    {        if([view.superview isKindOfClass:NSClassFromString(@"UIViewControllerWrapperView")])        {            Ivar ivar = class_getInstanceVariable([UIView class], "_viewDelegate");            viewController = object_getIvar(view, ivar);        }        else blocks(view.superview);    };    blocks(view);    return viewController;}

功能实现；

自豪之余，发现朋友发出新方法：

- (UIViewController *)findViewController:(UIView *)sourceView{    id target=sourceView;    while (target) {        target = ((UIResponder *)target).nextResponder;        if ([target isKindOfClass:[UIViewController class]]) {            break;        }    }    return target;}

当然，他是百度的（鄙视之）；

两人刚准备兴奋发现另一人发出：

//nav为root UINavigationControllerUIViewController *viewController = ((AppDelegate *)[UIApplication sharedApplication].delegate).nav.visibleViewController;

当时我们就震惊了～～～